Integer to English Words
Convert a non-negative integer to its english words representation. Given input is guaranteed to be less than 231 - 1.
For example,
123 -> "One Hundred Twenty Three"12345 -> "Twelve Thousand Three Hundred Forty Five"1234567 -> "One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven"
先把数字分割成4个三分位处理。前3个三分位分别加上Billion,Million,Thousand。
三分位处理函数为Helper()
class Solution {public: string Helper(string numStr, string dict1[], string dict2[], string dict3[]) { int num = atoi(numStr.c_str()); if(num == 0) return ""; else { string ret = ""; int hundred = numStr[0] - '0'; int ten = numStr[1] - '0'; int one = numStr[2] - '0'; if(hundred != 0) ret += dict1[hundred-1] + " Hundred"; if(ten == 0) { if(one == 0) return ret; else return (ret=="")?(dict1[one-1]):(ret+" "+dict1[one-1]); } else if(ten == 1) { return (ret=="")?(dict2[one]):(ret+" "+dict2[one]); } else { if(one == 0) return (ret=="")?(dict3[ten-2]):(ret+" "+dict3[ten-2]); else return (ret=="")?(dict3[ten-2]+" "+dict1[one-1]):(ret+" "+dict3[ten-2]+" "+dict1[one-1]); } } } string numberToWords(int num) { if(num == 0) return "Zero"; else { string ret = ""; string dict1[9] = { "One","Two","Three","Four","Five","Six","Seven","Eight","Nine"}; string dict2[10] = { "Ten","Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen", "Eighteen","Nineteen"}; string dict3[8] = { "Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"}; string numStr = to_string(num); int len = numStr.size(); string padding = string(12-len, '0'); numStr = padding + numStr; string billionStr = Helper(numStr.substr(0,3), dict1, dict2, dict3); if(billionStr != "") ret += billionStr + " Billion"; string millionStr = Helper(numStr.substr(3,3), dict1, dict2, dict3); if(millionStr != "") ret += (ret=="")?(millionStr+" Million"):(" "+millionStr+" Million"); string thousandStr = Helper(numStr.substr(6,3), dict1, dict2, dict3); if(thousandStr != "") ret += (ret=="")?(thousandStr+" Thousand"):(" "+thousandStr+" Thousand"); string oneStr = Helper(numStr.substr(9,3), dict1, dict2, dict3); if(oneStr != "") ret += (ret=="")?(oneStr):(" "+oneStr); return ret; } }};